log(base 9)X + 3log(base 3)X = 14
let log9 x = y then 9^y = x 3^2y = x and log3 x = 2y so log9 x = 2log3 x then log(base 9)X + 3log(base 3)X = 14 becomes 2log3 + 3log3 - 14 5log3 = 14 log3 = 2.8 x = 3^2.8 = 21.674
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