elimination method
1> 7x+15y=32
x-3y=20
multipy the second equation by 5, then add the equations.
can u help me with my homework
well i did as you said but my answer comes in fraction....can you help me say where i am wrong?
i did it in this way
7x+15y=32
5x-15y=100
----------
2x=132
x=132/2
x=66
then
x-3y=20
66-3y=20
-3y=20-66
-3y=-46
y=-46/3
now i know i am wrong. can someone please correct me plz....
You should be ADDING the 2 equations...so it should be 12x = 132, instead of 2x = 132
Question 5 of 8
Multiple Choice: Please select the best answer and click "submit."
The rule below shows how to find the distance traveled of an object thrown downward with initial
The elimination method is a technique used in solving a system of linear equations. In this method, we aim to eliminate one variable by manipulating the equations given.
To solve the system of equations:
1. First, multiply the second equation by 7 to make the coefficients of x the same in both equations:
7(x - 3y) = 7(20)
7x - 21y = 140
2. Now, we have the system of equations:
7x + 15y = 32
7x - 21y = 140
3. To eliminate x, subtract the second equation from the first equation:
(7x + 15y) - (7x - 21y) = 32 - 140
This simplifies to:
36y = -108
4. Divide both sides of the equation by 36 to solve for y:
y = -108 / 36
y = -3
5. Substitute the value of y back into one of the original equations to solve for x. Let's use the second equation:
x - 3(-3) = 20
x + 9 = 20
x = 20 - 9
x = 11
Therefore, the solution to the system of equations is x = 11 and y = -3.