Calculate the number of C, H, and O atoms in 4.50 g of glucose (C6H12O6), a sugar.
help please?
how many moles are in 4.5g?
How many molecules in one mole?
How many molecules in 4.5g?
Then, there are 6C for every molecule, and so on.
To calculate the number of C, H, and O atoms in a given mass of glucose (C6H12O6), you need to follow these steps:
1. Determine the molar mass of glucose:
The molar mass of glucose (C6H12O6) is calculated by summing the atomic masses of its constituent atoms.
C: 6 carbon atoms x atomic mass of carbon (12.01 g/mol) = 72.06 g/mol
H: 12 hydrogen atoms x atomic mass of hydrogen (1.01 g/mol) = 12.12 g/mol
O: 6 oxygen atoms x atomic mass of oxygen (16.00 g/mol) = 96.00 g/mol
Therefore, the molar mass of glucose is 72.06 g/mol + 12.12 g/mol + 96.00 g/mol = 180.18 g/mol.
2. Calculate the number of moles of glucose:
Using the formula: Moles = Mass / Molar mass
Moles = 4.50 g / 180.18 g/mol ≈ 0.025 moles.
3. Determine the number of atoms for each element:
Since one mole of any substance contains Avogadro's number of particles, which is approximately 6.02 x 10^23, you can use this value to calculate the number of atoms.
Number of atoms = Moles x Avogadro's number
For carbon (C): 0.025 moles x 6.02 x 10^23 atoms/mol = 1.506 x 10^22 atoms.
For hydrogen (H): 0.025 moles x 6.02 x 10^23 atoms/mol = 1.506 x 10^22 atoms.
For oxygen (O): 0.025 moles x 6.02 x 10^23 atoms/mol = 1.506 x 10^22 atoms.
Therefore, in 4.50 g of glucose (C6H12O6), there are approximately 1.506 x 10^22 carbon atoms, 1.506 x 10^22 hydrogen atoms, and 1.506 x 10^22 oxygen atoms.