Algebra
posted by George
Please help me solve:
[SQRT(x)]=2
1.
[SQRT(2x2  1)]=x

Reiny
[SQRT(x)]=2
has no solution since by definition √ gives only positive result.
for verification graph f(x) = √x + 2
it never touches or crosses the xaxis
for the second, I assume you mean
√(2x^21) = x
square both sides
2x^21 = x^2
x^2 = 1
x = ±1
but since we squared, both answers must be verfied.
if x=1
LS = √(21) = 1
RS = 1, so it works
if x=1
LS = √(21) = 1
RS = 1 , does not work
so x = 1
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