posted by Sharika .
If Jane had $0.58 in quarter(s), dime(s), nickle(s), and pennies she has a total of 9 coins. What coins does Jane have?
to have 58 cents, we know she must have had 3 pennies.
so there are 6 left for the dimes and nickels
n+d = 6, n = 6-d
by value : 5n + 10d + 3 = 58
n+2d = 11, combine with n=6-d and solve.
Diane has $1.95 in dimes and nickels. She has a total of 25 coins. How many of each kind does she have?