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If Jane had $0.58 in quarter(s), dime(s), nickle(s), and pennies she has a total of 9 coins. What coins does Jane have?

  • Math -

    to have 58 cents, we know she must have had 3 pennies.
    so there are 6 left for the dimes and nickels
    n+d = 6, n = 6-d

    by value : 5n + 10d + 3 = 58
    n+2d = 11, combine with n=6-d and solve.

  • Math -

    Diane has $1.95 in dimes and nickels. She has a total of 25 coins. How many of each kind does she have?

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