Physics

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Two knights on horseback start from rest 88.0 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of .300 m/s^2, while Sir Alfred's has a magnitude of .200 m/s^2. Relative to sir Ggeorge's starting point, where do the knights collide?

  • Physics -

    The sum of the distances is 88m.
    They collide at time t.

    d=1/2 .300*t^2
    88-d=1/2 .200 t^2

    divide the second equation by the first will lead to this

    88-d=d(2/3) solve for d

  • Physics -

    thanks

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