Math
posted by Momo .
Find an equation of the parabola with vertex at the origin that passes through the point (36, 2) and opens to the left.
I believe you start with (xh)^2 = 4p(yk) and plug in the given point and (0,0), and solve for p.
I got y^2 = 144x. Is this correct?
Thank you!

since the vertex is at the origin and the parabola opens to the left, it would have the simple form
x = ay^2
plug in (36,2) to get a = 9
so the equation is x = 9y^2
you should have realized your answer was wrong since the given point does not even satisfy your equation.
Secondly it would open to the right.
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