r^2-r(@a-b)-2ab

I don't understand the @ sign. Is it supposed to be an unknown variable?

Mistake...

the @ is 2

(r-2a)(r+b) does that work?

thanks

To simplify the expression r^2 - r(@a-b) - 2ab, we can follow the order of operations and combine like terms.

Let's break it down step by step:

Step 1: Expand the term r(@a-b)
Since there is a multiplication between r and (@a-b), we can distribute r to both @a and -b.
=> r * @a - r * (-b)
=> ra + rb

Now the expression becomes r^2 - (ra + rb) - 2ab

Step 2: Combine like terms
We have two terms with the variable "r": r^2 and -ra.
Since they both have "r" as a common factor, we can combine them:
=> r^2 - ra

The expression now simplifies to (r^2 - ra) - rb - 2ab

Step 3: Combine like terms
Since we have two terms with the variable "b": -rb and -2ab, we can combine them:
=> (r^2 - ra) - (rb + 2ab)

The final simplified expression is: (r^2 - ra) - (rb + 2ab)

Remember, when simplifying expressions, it's important to follow the order of operations and combine like terms to simplify further.