What is the system of equations for a feasible region with vertices at (-3,2) (1,3) (6,1) and (2,-2)?
Those would be vertices of a quadrilateral formed by lines connecting (-3,2) and (1,3); (1,3)and (6,1); (6,1) and (2,-2); and (2,-2) and (-3,2). Drawing a graph will help you confirm that is the "feasible region". You can figure out equations for the lines that are the sides of the quadrilateral, if that is what you are after. The first line would be
y = x/4 + 11/4 (domain -3 to 1).