Chemistry help needed

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How do I prepare 90% formic acid from conc. formic acid (98%-100% of density 1.22g/ml)?

Please help me check if my calculations are correct.

Assuming conc. formic acid is 99%,

0.99 X 1.22 = 1.2078
Add 1.2078 / 9 = 0.1342ml H2O to 1ml of conc. acid to have a solution that is 90% formic acid by mass.

Let V be the volume of conc. formic acid needed.
0.1342V = 1000 – V
i.e. V = 881.7ml

Hence I will need to add 881.7ml of conc formic acid & make up to 1L with water?

Thank you.

  • Chemistry help needed -

    (0.99)(1.22g.soln/ml) = 1.2078 g pure acid / mL original soln.
    To get 100.0 g of pure acid:
    (100.0g) / 1.2078 g acid / mL = 82.8 mls original solution. The total weight of that solution is:
    (82.8 mls)(1.22g/ml) = 101g)
    (Let the diluted solution contain 100.0g pure acid = m)
    100.0g /m = 0.900
    solving,
    m = 111 g total new solution
    Total mass - 99% cid mass = mass of H2O
    111g - 101g = 10.0g water added
    The recipe for making the new solution is
    10.0mls of water added to 82.8 mls 99% solution
    to make 92.8 mls 90% solution.
    Now I will let you scale up the recipe to 1000 mls of 90% solution.

  • Chemistry help needed -

    Thank you for your explanation.Is there any formula that we can apply universally for preparations of this nature(w/w)?

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