Post a New Question

Physics - Fluids

posted by .

A cylindrical diving bell 3.0 m in diameter and 4 m tall with an open top of 25 degrees celsius, and the air temp 220 down is 5 degrees celsius. The density of seawater is 1025 kg/m^3. How high does the sea water rise in the bell when the bell is submerged?

  • Physics - Fluids -

    solve for the new volume of air in the bell..

    V2=V1P1T2/P2T1

    Then the height will be (V1-V2)/V1 *4m

    Temps have to be in Kelvins.

    To get pressure, consider a column 1 m^2.

    The weight of that column is 1m^2*height*density*g
    so pressure at the 220m down is
    P2=101.3kpa+220*densityseawater*g Pa and
    P2=101.3kPa+.220*density*9.8 in kPa

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question