physics
posted by help .
A train moving at a constant speed of 68.0 km/h moves east for 33.0 min, then in a direction 40.0° east of due north for 30.0 min, and then west for 59.0 min. What is the average velocity of the train during this run?
Magnitude
km/h

The key is finding the final position.
1) It goes 68*33/60 km east
2) it goes 68*30/60 40 deg E of N. Converting that to E and N displacements..
it goes 60(30/60)sin40 East
it goes 60(30/60)cos40 North
3) it goes E for 68(59/60) Notice the negative sign which changes West to East.
Now add up the East components.
That gives you the net East.
Now add up the N components.
Now use Pythogerean theorum
displacement=sqrt(N^2 +E^2)
Magnitude avg velocity=displacement/timetotal.