math

posted by .

the revenue R from selling x units of a certain product is given by R=x(20-0.2x)
How many units must be sold to produce a revenue of \$500?

• math -

You will need to solve for x in the following equation:

500 = x(20-0.2x)

• math -

factor it out
500 = 20x -0.2x^2
0.2x^2 - 20x + 500 = 0
divide the whole equation by 0.2
x^2 - 100x + 2500 = 0
(x-50)^2
R=50

• math -

i got 500=20x-0.2x^2

whats the next step?
=\

Similar Questions

1. algebra

the revenue from selling x units of a product is given by y=-0.0002x^2+60x. how many units must be sold in order to have the greatest revenue?
2. Calculus

Suppose the revenue from producing and selling x units of a given product is given by R(x)=10x-0.02x^2 a) Find the number of units produced if the revenue is \$800. I really need help with this, I don't know what to do?
3. Calculus

If the derivative can be thought of as a marginal revenue function for x units (in hundreds of items) sold, and the revenue for a company is given by the function. R(x) = 30x^3 ¨C 120x^2 + 500 f or 0 ¡Ü x ¡Ü 100, a. Sketch the …
4. Calculus

If the derivative can be thought of as a marginal revenue function for x units (in hundreds of items) sold, and the revenue for a company is given by the function. R(x) = 30x^3 ¨C 120x^2 + 500 f or 0 ¡Ü x ¡Ü 100, a. Sketch the …
5. Calculus

If the derivative can be thought of as a marginal revenue function for x units (in hundreds of items) sold, and the revenue for a company is given by the function. R(x) = 30x^3 - 120x^2 + 500 f or 0 ¡Ü x ¡Ü 100, a. Sketch the graphs …
6. Calculus

If the derivative can be thought of as a marginal revenue function for x units (in hundreds of items) sold, and the revenue for a company is given by the function. R(x) = 30x^3 - 120x^2 + 500 for 0 _< x _< 100, a. Sketch the …
7. Calculus

If the derivative can be thought of as a marginal revenue function for x units (in hundreds of items) sold, and the revenue for a company is given by the function. R(x) = 30x^3 - 120x^2 + 500 for 0 _< x _< 100, a. Sketch the …
8. College Algebra (Urgent)

The demand equation for a product is p = 60 – 0.0004x, where p is the price per unit and x is the number of units sold. The total revenue for selling x units is shown below. Revenue = xp = x(40 – 0.0004x) How many units must be …
9. math

In economics, revenue Upper R is defined as the amount of money derived from the sale of a product and is equal to the number x of units sold times the selling price p of each unit. If the selling price is given by the equation p -1/10x+60 …
10. Math

The revenue from the sale of a product is, in dollars, R = 1500x + 3000(2x + 3)^−1 − 1000 where x is the number of units sold. Find the marginal revenue when 150 units are sold. (Round your answer to two decimal places.)

More Similar Questions