Balance the following equastions:

Fe2O3 +c --> Fe +CO2

SO2 + O2 --> SO3

for physical science.. the numbers are subscripts.. thank you.

1) 2,3,4,3

2)2,1,2

To balance chemical equations, we need to ensure that the number of atoms on the reactant side is equal to the number of atoms on the product side. Let's balance the given equations step by step:

1. Fe2O3 + C --> Fe + CO2

We have two iron atoms on the left side, so we need two iron atoms on the right side. We can add a coefficient of 2 in front of Fe so that it becomes Fe2.

Fe2O3 + C --> Fe2 + CO2

Next, we have three oxygen atoms on the left side due to the subscript 3 in Fe2O3. We have four oxygen atoms on the right side due to the subscript 2 in CO2. To balance the oxygen atoms, we can add a coefficient of 2 in front of CO2.

Fe2O3 + C --> Fe2 + 2CO2

The equation is now balanced with equal numbers of atoms on both sides.

2. SO2 + O2 --> SO3

The equation already has the same number of sulfur atoms on both sides. Let's balance the oxygen atoms.

We have two oxygen atoms on the left side due to the subscript 2 in SO2. We have three oxygen atoms on the right side due to the subscript 3 in SO3. To balance the oxygen atoms, we can add a coefficient of 3/2 (or 1.5) in front of O2.

SO2 + 1.5O2 --> SO3

However, it is generally preferred to have whole number coefficients in balanced equations. We can multiply the entire equation by 2 to eliminate the fractional coefficient.

2SO2 + 3O2 --> 2SO3

The equation is now balanced with equal numbers of atoms on both sides.

Final balanced equations:
1. Fe2O3 + C --> Fe2 + 2CO2
2. 2SO2 + 3O2 --> 2SO3