posted by Lilit .
A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 degrees to the right of her original course, and flies 2 h in the new direction. If she maintains a constant speed of 680 mi/h, how far is she from her starting position?
1020 miles in the first direction and 1360 miles in the second direction. Add them as vectors.
The distance traveled has components of
1360 + 1020 cos 10 = 2364.5 in the final direction and 1020 sin 10 = 177.1 in the perpendicular direction. The resultant is
sqrt (2364.5^2 + 177.1^2) = 2371.1 miles