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A pilot flies in a straight path for 1 h 30 min. She then makes a course correction, heading 10 degrees to the right of her original course, and flies 2 h in the new direction. If she maintains a constant speed of 680 mi/h, how far is she from her starting position?

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    1020 miles in the first direction and 1360 miles in the second direction. Add them as vectors.

    The distance traveled has components of
    1360 + 1020 cos 10 = 2364.5 in the final direction and 1020 sin 10 = 177.1 in the perpendicular direction. The resultant is
    sqrt (2364.5^2 + 177.1^2) = 2371.1 miles

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