A sailor strikes the side of his ship just below the waterline. He hears the echo of the sound reflected from the ocean floor directly below 1.85 s later. How deep is the ocean at this point?
2d=velocitysound*time
480.48m
To determine the depth of the ocean at this point, we need to use the formula:
Depth = (Speed of sound × Time) / 2
The speed of sound in water is approximately 1,500 meters per second. Plugging in the values:
Depth = (1500 m/s × 1.85 s) / 2
Depth = 2775 m / 2
Depth ≈ 1387.5 meters
Therefore, the ocean at this point is approximately 1387.5 meters deep.
To determine the depth of the ocean at the point where the sailor struck the side of the ship, we can use the speed of sound in water, as well as the time delay of the echo. Here's how we can calculate it:
1. Determine the speed of sound in water: The speed of sound in water is approximately 1500 meters per second. This value may vary slightly depending on factors like temperature and salinity, but 1500 m/s is a reasonable estimate.
2. Calculate the distance traveled by the sound: The sound wave travels from the sailor's ship to the ocean floor and back. Since the sound has traveled twice the depth of the ocean, we need to divide the total distance by 2. This can be calculated using the formula:
Distance = Speed * Time
Given that the time delay is 1.85 seconds, the distance traveled by the sound waves is:
Distance = 1500 m/s * 1.85 s
3. Determine the depth of the ocean: Since the sound wave has traveled twice the depth of the ocean, we need to divide the distance by 2. This gives us the depth of the ocean at that point:
Depth = (Distance traveled by sound) / 2
Calculating the depth:
Depth = (1500 m/s * 1.85 s) / 2
Simplifying this:
Depth = 2775 m / 2
Therefore, the depth of the ocean at the point where the sailor struck the side of the ship is approximately 1387.5 meters.