9TH GRADE ALGEBRA

posted by .

solve for the variable

ã(square root)
ãy+6 - ãy = ã2

would i square both sides first?
im stuck

  • 9TH GRADE ALGEBRA -

    yes, then use the quadratic equation.

  • 9TH GRADE ALGEBRA -

    its is y times the 5th power of 8 or using the quadradic eqaution it bis something else

  • 9TH GRADE ALGEBRA -

    the eqaution is the reciprical of the times of 6 to the 10th power of A or the quadratic eqaution

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Inter. Algebra

    I find it curious here: a - b=2 in this case, rationalize by multplying both sides by a+b, getting a-b=2 a^2-b^2=2(a+b) 2x+3-x+2=2(a+b) (x+5)/2 = a+b now add the original equation.. 2= a-b or 2a= 2+ x/2 + 5/2 4sqrt(2x+3)= x+9 square …
  2. math,correction

    Is this correct: Problem #13 Solve: 9x^2 = 14 I did the following i divided 9 by both sides then i get this: x^2 = 1.5555555 then i squared both sides and i got the following answer: x = 1.24 I would not have used decimals x^2 = 14/9 …
  3. Algebra

    Solve 2+ the square root of 4-x=x what is your question?
  4. algebra

    1.)correct 2.)wrong---> the first term is wrong 4(3a^2)^2 = 36a^4 3.) not sure on this one 4.) wrong---> - square root of six is not a solution Hope this Helps! 1)find p(-3)if p(x)=4x^3-5x^2+7x-10 =-184 2)If r(x)=4x^2-3x+7,find …
  5. Pre Algebra

    Please help me with some problems. Thank you! Solve the equation by square root property. 3. 2x^2 = 26 I don't understand how to solve this problem. Solve the equation using the quadratic formula. 7. 7x^2=-8x -2 This is what I got …
  6. Math

    Just need some help... Directions: Multiply or raise to the power as indicated... Then simplify the result. Assume all variables represent positive numbers. 1. 5(square root of 6) times two-thirds(square root of 15)= 3 one-third (square …
  7. Algebra

    Use the quadratic formula to solve the equation. Give exact answers: 2x^2 -1 = 6x. The choices are: a) -3 + square root(7)/2, -3 - square root(7)/2 b) 3 + square root(11)/2, 3 - square root(11)/2 c) 3 + square root(7)/2, 3 - square …
  8. Pre Calculus

    square root of 3x-4 = (x-4)^2-3 Normally, I either take the square root of both sides or I square both sides. Since there is a sqared and a square root, I am confused on how to go about it. Could you please head me in the right direction?
  9. Pre-Calculus

    (not sure how to type square root of) square root of 3x - 4 = (x-4)^2-3 Normally, I either take the square root of both sides or I square both sides. Since one side of the equation is square root of 3x-4 and the other side is (x-4) …
  10. Algebra

    Rationalize each expression by building perfect nth root factors for each denominator. Assume all variables represent positive quantities. I don’t understand how to compute these. Also I don’t have the square root sign so I typed …

More Similar Questions