if a refrigerator cools 200g of water from 20degrees celcius to it freezing point in 10mins, how much heat is removed per minute from the water?
heat removed= mass*specificheat*deltaTemp
Bitvh
To determine the amount of heat removed per minute from the water, we can use the equation:
Q = mcΔT
Where:
Q = amount of heat transferred
m = mass of the water
c = specific heat capacity of water
ΔT = change in temperature
To find the specific heat capacity of water, we can refer to standard values. The specific heat capacity of water is approximately 4.186 J/g°C.
Given:
Mass of water (m) = 200g
Initial temperature (T1) = 20°C
Final temperature (T2) = 0°C (freezing point)
Time (t) = 10 minutes
First, calculate the change in temperature:
ΔT = T2 - T1
= 0°C - 20°C
= -20°C
Next, calculate the amount of heat transferred (Q) from the given values:
Q = mcΔT
= (200g) * (4.186 J/g°C) * (-20°C)
= -16,744 J
To find out the amount of heat removed per minute, divide the total heat transfer by the time taken:
Heat removed per minute = Q / t
= (-16,744 J) / (10 min)
= -1674.4 J/min
Therefore, approximately -1674.4 Joules of heat are removed per minute from the water. The negative sign indicates heat removal.