posted by jacob .
hmm...i need help on this problem, anyone know how to o this? (if u can, put a step-by-step solution) i would really be grateful.
the coordinates of two points are A(-2,6) and B(9,3). find the coordinates of the point C on the X-axis so that AC=BC
If it is on the X axis, y = 0. All you have to do is solve for x.
The distance of a point on the x axis from A is
D1 = sqrt [(x+2)^2 + 6^2}
and the distance from B is
D2 = sqrt [(x-9)^2 + 3^2]
Set D1 = D2, (or D1^2 = D2^2) and solve for x.
x^2 + 4x + 4 + 36 = x^2 -18x + 81 + 9
22 x = 90 - 40 = 50
x = 50/22 = 2.273