How many kids do you have:4? How many different ways can you arrange this other than these?: [g=girl;b=boy]
2 g 2 b
3 g 1 b
4 g
4 b
i also forgot 3 b 1 g
Without getting into birth order, your answer is right.
thanks. yes birth order would be something like 1 g 1 b 1 b 1 g but that would be too confusing! Don't want to hurt your mind with all that :D
-MC
To find the different ways you can arrange 4 kids, 2 girls (g) and 2 boys (b), we can use the concept of permutations. A permutation is the arrangement of objects in a specific order.
In this case, we have 4 kids, so there are 4 positions to fill. Let's assign the positions as follows: Position 1, Position 2, Position 3, and Position 4.
Now we need to consider the possibilities for each position:
Position 1: It can be either a girl (g) or a boy (b). So, there are 2 possibilities (g or b).
Position 2: It also has 2 possibilities since it can be a girl or a boy as well.
Position 3: Similarly, it has 2 possibilities.
Position 4: Once again, it has 2 possibilities.
To find the total number of arrangements, we multiply the number of possibilities for each position:
Total arrangements = Possibilities for Position 1 × Possibilities for Position 2 × Possibilities for Position 3 × Possibilities for Position 4
Total arrangements = 2 × 2 × 2 × 2 = 16
Therefore, there are 16 different ways to arrange 4 kids, 2 girls, and 2 boys.
The different arrangements are as follows:
1. g g b b
2. g b g b
3. g b b g
4. b g g b
5. b g b g
6. b b g g
7. g b b b
8. b g g g
9. g g g b
10. g g b g
11. g b g g
12. b g g g
13. g b g g
14. b g b b
15. b b g b
16. b b b g
Note: The arrangements where all the girls are together (e.g., g g g b) or all the boys are together (e.g., b b b g) are not included in the list, as they are already accounted for in the options you provided (4g and 4b).