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physics

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At what altitude above Earth's surface would the gravitational acceleration be 3.0 m/s2?

  • physics -

    I am not going to do all this arithmetic
    F/m = g apparent = 3 = G Mearth/(Rearth +h)^2
    where we know
    9.8 = G Mearth/Rearth^2
    so
    9.8/3 = (Rearth+h)^2 / Rearth^2

  • physics -

    Let:
    m = a small mass
    M = mass of the earth
    r = distance from the center of mass m to the earth's center.
    Constants:
    G = 6.67x10^-11 m^3/kg.s^2.
    M = 5.98x10^24 kg
    R = 6.38x10^6 m (Earth's radius)
    Law Of Gravitation:
    F = GmM/r^2
    F = m(GM/r^2) = mg
    GM/r^2 = 3.00 m/s^2
    Solve for r and subtract the radius of the earth.

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