posted by Confused .
What is The solution set of 2k^2=21k-49 ?
this an be arranged to the quadratic
2k^2 - 21k + 49 = 0
(2k-7)(k-7) = 0
k = 7/2 or k-7
Thanks! how do u determine that they are both -7 though? Doesn't it have to equal 21? or doesn't that 21 matter?
why don't you expand (2k-7)(k-7 to see what you get?
oh it makes sense now thanks!
what is Expand:-4(2m - 7x + 9)