math
posted by Confused .
What is The solution set of 2k^2=21k49 ?

this an be arranged to the quadratic
2k^2  21k + 49 = 0
(2k7)(k7) = 0
k = 7/2 or k7 
Thanks! how do u determine that they are both 7 though? Doesn't it have to equal 21? or doesn't that 21 matter?

why don't you expand (2k7)(k7 to see what you get?

oh it makes sense now thanks!

what is Expand:4(2m  7x + 9)