algebra
posted by lisa .
jill has $ 9.96 in nickles pennies and dollar bills. she has 12 more pennies than nickles and 5 less dollar bills than nickles.

I'm sorry about the other post. I didn't post it. Whoever did post it will not be posting again on this board.
I'm sorry, but I can't help you with this question, but I'm sure someone will show you how to do it. 
let the number of nickels be x
let the number of pennies be x+12
let the number of dollar bills be x5
now we will think of the "value" of our money
1(x+12) + 5(x) + 100(x5) = 996
solve for x
let me know what you got. 
996=5n+p+100d
12+n=p
n5=d
n=nickels
p=pennies
d=dollars
996=5n+(12+n)+100(n5)
1484=106n
n=14
p=12+n=12+14=26
d=n5=145=9
double check
996=5(14)+26+100(9)
996=996
hope this helps
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