Post a New Question

Math

posted by .

Can some one help me solve this please.

2e^5x = 712

log5 80= the five is little next to the log

and 2logx=log(6x-90)+1

thanks I would really appriciate it if you could help me out

  • Math -

    You need a pocket calculator or function table to get numerical answers.

    2e^(5x) = 712
    e^(5x) = 356
    5x = ln 356 = 5.8749
    x = 1.17499

    log(5) 80 = x
    5^x = 80
    x log 5 = log 80 (any base)
    x = 2.7227

    log [(6x-90)/x^2] = -1
    You need to specify the log base. If the log base is 10
    [(6x-90)/x^2] = 0.1
    If the log base is e, 1/e goes on the right side.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question