HS Calculus
posted by jane .
Let f(x) = 2/3x
a) find the slope of the tangent to the graph of f at a general point x0 using the definition of the dervative.
b) use the result in part a to find the slope of the tangent at x0=1.
I am very confused.
My answer for (a) 1/ 66xx^2
(b) 1
I compared them to a classmate  answers didn't agree.
I am lost.

How did you get that derivative?
I rewrote the equation to
y = 2(3x)^1
then y' = 2(3x)^2(1)
= 2/(3x)^2 or 2/(x^2  6x + 9)
so when x=1, y' = 2/(31)^2 = 1/2