# Math

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The critical numbers of the function:
f(t)=7t^(2/3)+t^(5/3)

f'(t)=14/3t^(-1/3)+(5/3)t^(2/3)
I got 0 as a critical number but it is hard for me to factor the f'(t). Whats the other critical number? Thank you.

• Math -

If 14/3t^(-1/3)+(5/3)t^(2/3)= 0, then

t^(-1/3) [14/3 + (5/3)t] = 0
t = 0 or -14/5

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