at 30degrees celcius, 80 grams of potassium bromide is dissolved in 100 grams of water. is this solution unsaturated, saturated, or supersaturated.
You need to have a graph of the solubility or a table listing the solubility. I don't have those.
Note the correct spelling of Celsius.
You'd have to look up the solubility of that compound in water to come up with an answer. I am surprised that they would assign such a question in 9th grade science. My handbook of physics and chemistry states that 53 grams of KBr will dissolve in 100 g of water at 0 C and 102 g will dissolve at 100 C. It is likely that about 65-75 g will dissolve in a saturated solution at 30 C. That would mean the solution is supersaturated. It could however be saturated. It is too close to call with the data I have. My handbook does not have the solubility at 30 C.
Were you possibly given a graph of solubility vs. temperature as part of this question? If so, that will tell you the answer.
My supposition was that a graph was furnished.
This solution is supersaturated because solubility of KBr at 30*C is 70.7 so it is supersaturated
To determine if a solution is unsaturated, saturated, or supersaturated, we need to compare the amount of solute (in this case, potassium bromide) dissolved in the solution to its solubility at the given temperature (30 degrees Celsius).
The solubility of potassium bromide in water is the maximum amount of potassium bromide that can dissolve in a given amount of water at a specific temperature. If the amount of potassium bromide dissolved is less than the solubility, the solution is unsaturated. If the amount of potassium bromide dissolved is equal to the solubility, the solution is saturated. And if the amount of potassium bromide dissolved is more than the solubility, the solution is supersaturated.
To find the solubility of potassium bromide at 30 degrees Celsius, we would need to refer to a solubility table or graph specific to this substance. Unfortunately, I don't have the ability to look up specific solubility values.
However, based on the information provided (80 grams of potassium bromide dissolved in 100 grams of water), we can make an inference. If the 80 grams of potassium bromide is less than the solubility at 30 degrees Celsius, then the solution would be unsaturated. If it is exactly equal to the solubility, the solution is saturated. And if it is greater than the solubility, the solution is supersaturated.
Therefore, without knowing the exact solubility of potassium bromide at 30 degrees Celsius, we cannot determine whether the solution is unsaturated, saturated, or supersaturated.