When combined with cupric ions (aq, 1M) which will produce the largest standard cell voltage?
a. ) KMnO4(aq)
b. ) MnO2(s)
c. ) MnCl2(aq)
d. ) Mn(s)
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how do you find the standard electrode potentials of KMnO4 and MnCl2?
and is the standard electrode potential of MnO2 1.28?
To determine which substance will produce the largest standard cell voltage when combined with cupric ions (Cu2+), we need to consider the standard reduction potentials of each substance and compare them.
The standard reduction potential is a measure of the tendency of a species to gain electrons and get reduced in a chemical reaction. The more positive the reduction potential, the stronger the tendency to gain electrons and get reduced.
To solve this, we need to compare the standard reduction potentials of Cu2+ with the reduction potentials of the substances given in the options: KMnO4(aq), MnO2(s), MnCl2(aq), and Mn(s).
First, we need to find the standard reduction potential for Cu2+. We can look up the reduction potential table, also called the electrochemical series. Let's assume the standard reduction potential for Cu2+ is given as +0.34V.
Now, let's compare it with the reduction potentials of the substances given in the options.
a) KMnO4(aq): We need to find the standard reduction potential for KMnO4 in the table. Let's assume it is +1.50V.
b) MnO2(s): We need to find the standard reduction potential for MnO2 in the table. Let's assume it is +0.60V.
c) MnCl2(aq): Since MnCl2 is an ionic compound, we need to find the standard reduction potential for Mn2+ in the table. Let's assume it is +1.18V.
d) Mn(s): We need to find the standard reduction potential for Mn in the table. Let's assume it is -1.18V.
To calculate the overall cell voltage, we subtract the reduction potential of the anode (where oxidation occurs) from the reduction potential of the cathode (where reduction occurs) in a galvanic cell.
Since Cu2+ is the cathode (reduction occurs at the cathode), we need to choose the substance with the largest reduction potential as the anode.
Comparing the reduction potentials:
a) +1.50V - +0.34V = +1.16V
b) +0.60V - +0.34V = +0.26V
c) +1.18V - +0.34V = +0.84V
d) -1.18V - +0.34V = -1.52V
Based on these calculations, the substance that will produce the largest standard cell voltage when combined with cupric ions (Cu2+) is KMnO4(aq) (option a) with a standard cell voltage of +1.16V.