A tube has gas within it whose volume equals 250 liters at a temperature of 300 celsius K . If the pressure of the gas is kept constant, what will the temperature be if the gas volume is increased by 50 liters ?
a temperature can't be celsius and K at the same time. which one is it?
To determine the final temperature when the gas volume is increased by 50 liters while the pressure remains constant, we can use Charles' Law, which states that the volume of a gas is directly proportional to its temperature when pressure is held constant.
Charles' Law can be mathematically expressed as:
V1 / T1 = V2 / T2
where:
V1 = Initial volume of the gas
T1 = Initial temperature of the gas
V2 = Final volume of the gas
T2 = Final temperature of the gas
Let's plug in the given values:
V1 = 250 liters
T1 = 300 Celsius = 300 + 273 = 573 Kelvin
V2 = 250 + 50 = 300 liters (volume increased by 50 liters)
Now we can rearrange the equation and solve for T2:
(V1 * T2) / T1 = V2
T2 = (V2 * T1) / V1
T2 = (300 * 573) / 250
Calculating the value:
T2 = 688.32 Kelvin
Therefore, the final temperature of the gas, when the volume is increased by 50 liters while the pressure remains constant, will be approximately 688.32 Kelvin.