Precalculus with applications
posted by Mary .
Name all the values of x that are not in the domain of f(x)=2x^2/x+5.
Answer: x=5

Precalculus with applications 
bobpursley
correct. Division is not defined by zero.

Precalculus with applications 
Mary
I thought so. Thanks
Respond to this Question
Similar Questions

Math
determine the domain. express in interval notation. y = rt(x^27x+10) i know this much y = rt[(x5)(x2)] now what do i do? 
math
Please help. Name all values of x that are not in the domain of the given function. f(x)=x10/(sqrt x^216) 
Function Notation
Ive been shown that a function can be written like so f:X>Y,f(x)=rule where X is the Domain and Y, the codomain. Firstly, what is the codomain? 
Precalculuscheck answers
Name all the values of x that are not in the domain of f(x)=2x^2/x+5. Answer: x= 5 2)Find the minimum value of f(x,y)=2xy+2 for the polygonal convex set determined by this system of inequalities: x >/= 1, x </= 3, y</=0, … 
Precalculus
Name all the values of x that are not in the domain of f(x)=2x^2/x+5. Answer: x= 5 2)Find the minimum value of f(x,y)=2xy+2 for the polygonal convex set determined by this system of inequalities: x >/= 1, x </= 3, y</=0, … 
precalculcus
Name all the values of x that are not in the domain of f(x)=2x^2/x+5. Answer: x= 5 2)Find the minimum value of f(x,y)=2xy+2 for the polygonal convex set determined by this system of inequalities: x >/= 1, x </= 3, y</=0, … 
PreCalculuscheck answers
Name all the values of x that are not in the domain of f(x)=2x^2/x+5. Answer: x= 5 2)Find the minimum value of f(x,y)=2xy+2 for the polygonal convex set determined by this system of inequalities: x >/= 1, x </= 3, y</=0, … 
Precalculus with applications
If f(x)=4x^2 and g(x)=2/x, find [g*f](x). answer I got: [g*f](x)=g(f(x)) =g(2/4x)^2 Is this right? 
pre calcheck
Name all the values of x that are not in the domain of f(x) = (2–x^2)/ (x+ 5) I got only x= 5 because that's the only value that would make the denominator zero. 
Algebra
23. The ___ axis represents the independent variable. X?