What is the boiling point of water at an elevation of 1.55×10^4 ft ?
The atmospheric pressure at sea level is 760mmHg . This pressure decreases by 19.8mmHg for every 1000-ft increase in elevation.
The boiling point of water decreases 0.05 degrees celsius for every 1mmHg drop in atmospheric pressure.
pressuredrop=1.55E4/1E3 (19.8mmHg)
solve that.
BP=100 - .05*pressure drop
To find the boiling point of water at an elevation of 1.55×10^4 ft, we need to calculate the change in atmospheric pressure and the corresponding change in boiling point.
First, let's calculate the change in atmospheric pressure:
Change in pressure = (elevation / 1000 ft) * (rate of pressure decrease)
Change in pressure = (1.55×10^4 ft / 1000 ft) * (19.8 mmHg/1000 ft)
Change in pressure = 307.8 mmHg
Next, let's calculate the change in boiling point:
Change in boiling point = (change in pressure) * (rate of boiling point decrease)
Change in boiling point = 307.8 mmHg * (0.05°C/1 mmHg)
Change in boiling point = 15.39°C
Now, we can find the boiling point at the given elevation by subtracting the change in boiling point from the boiling point at sea level:
Boiling point at elevation = Boiling point at sea level - Change in boiling point
Boiling point at elevation = 100°C - 15.39°C
Boiling point at elevation = 84.61°C
Therefore, the boiling point of water at an elevation of 1.55×10^4 ft is approximately 84.61°C.
To find the boiling point of water at an elevation of 1.55x10^4 ft, we need to consider the decrease in atmospheric pressure at that elevation.
1. Determine the change in atmospheric pressure from sea level to the given elevation.
- Pressure decreases by 19.8 mmHg for every 1000-ft increase in elevation.
- Divide the given elevation (1.55x10^4 ft) by 1000 and multiply by the pressure change (19.8 mmHg) to calculate the decrease in pressure.
Using the formula: Pressure change = (elevation / 1000) x pressure change per 1000 ft
Pressure change = (1.55x10^4 ft / 1000) x 19.8 mmHg
2. Subtract the pressure change from the sea level pressure to find the pressure at the given elevation.
- The sea level pressure is given as 760 mmHg.
Pressure at given elevation = Sea level pressure - Pressure change
3. Calculate the change in boiling point based on the pressure decrease.
- The boiling point of water decreases 0.05 degrees Celsius for every 1 mmHg drop in atmospheric pressure.
- Multiply the pressure change by 0.05 to find the change in boiling point.
Boiling point change = Pressure change x 0.05 degrees Celsius
4. Subtract the boiling point change from the boiling point of water at sea level to find the boiling point at the given elevation.
- The boiling point of water at sea level is 100 degrees Celsius.
Boiling point at given elevation = Sea level boiling point - Boiling point change
By following these steps, you will be able to determine the boiling point of water at an elevation of 1.55x10^4 ft.