my teacher gave us this question and i am totally confused on what to do. any help would be greatly appreciated.

Explain what is happening in the pseudo code LOOP in one word. What is temp referring to, and what is the final output for this program:

input (12, 25, 11, 28, 14)
BEGIN
temp := a_1
for i = 2 to n
if temp < a_i then temp := a_i
END
print temp
thank you for any help on this problem

Temp is a temporary variable.

Lets see. It reads the first value, stores it in temp1, then it reads the next variable, tests it to see if it is greater than the first variable, if so, it replaces it, if not it reads the next data, and so on.
It appears to me it returns the greatest value from the set of data.

thanks for the help

To understand what is happening in the pseudo code loop, you need to break it down step by step.

Step 1: Initialize the variable "temp" with the value of the first element a_1 in the input sequence.

Step 2: Start a loop that runs from the second element a_2 to the last element a_n.

Step 3: Compare the current value of "temp" with the current element a_i. If the current element is greater than "temp", update the value of "temp" to be equal to that element.

Step 4: Repeat Step 3 for all elements in the input sequence.

Step 5: After the loop ends, print the final value of "temp".

So, in one word, the pseudo code loop can be described as finding the maximum value in the input sequence.

Regarding the second part of your question, "temp" is referring to a temporary variable which is used to keep track of the maximum value found in the input sequence.

To find the final output for this program, we need to apply the pseudo code to the given input sequence: (12, 25, 11, 28, 14).

1. Initialize "temp" with the value of the first element: temp = 12.
2. Start the loop.
- Compare temp (12) with the second element (25). temp < 25, so update temp = 25.
- Compare temp (25) with the third element (11). temp > 11, so no update.
- Compare temp (25) with the fourth element (28). temp < 28, so update temp = 28.
- Compare temp (28) with the fifth element (14). temp > 14, so no update.
3. End the loop.
4. Print the final value of temp: 28.

Therefore, the final output for this program would be 28.