algebra 2
posted by Fred .
The width of a rectangle is 3ft less than the length, the area is 4ft^2 find the length and width

a=lw
w=l3
therefore
a=(l3)l
and a=4
therefore
4=l^23l
l=4(guess&check)
w=l3
w=43
w=1 
L=2
because...
a=lw
4=(13)L
4=2L
divide both sides by 2
2=L 
the length is l= 2
because area does equals length*width
which would be 4=(13)L
4=2L then you will have to divide both sides bby the negative 2
2=L
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