posted by .

can you please show me in steps how to find f(1+a)
in this equation
i know that you will plug in 1+a anywhere there is x. but after that i get confused.

also can you tell me how to find the domain and range of a relation
for ex. 2x+5y=10
thanks for your help!

  • trig -

    f(1+a) = -2(1+a)^2 + 4(1+a) + 6
    = -2(1 + 2a + a^2) + 4 + 4a + 6
    = -2 -4a -2a^2 + 10 + 4a
    = -2a^2 + 8

    for 2x+5y=10 both the domain and range are the real numbers
    You are looking at a slanted line, (slope=-2/5), so you will find the graph for whatever x you use, and for whatever y you use.
    This is true for all straight line graphs, which are neither vertical nor horizontal.

  • trig -

    ok,thanks alot.. what about this one : y=2x^2-5

  • trig -

    this is a vertical parabola, meaning it opens either upwards or downwards

    the domain of any vertical parabola is the set of real numbers

    for the range:
    if the parabola opens up, then y ≥ the y value of the vertex
    if the parabola opens down, then y ≤ the y value of the vertex

    in this case
    Domain : x any real number
    Range : y ≥ -5, y being real

  • trig -

    ok. so do u mean that to figure this out u always have to graph the relation?

  • trig -

    no, you just have to find the vertex.

    Here is a quick way to find the vertex:

    if y = ax^2 + bx + c

    then the x of the vertex is -b/(2a)
    sub that back into the function to find the y value.

  • trig -

    im sry im still kinda confused. can you show me once again please and explain everything you do thnks:

    y=4/square root of x^2+81

    thnks alot!!

  • trig -

    btw, why are you calling this "trig" ?

  • trig -

    its in the first chapter of my trig course. i know its review frm geometry and alg

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. maths

    I am really facing difficulty in maths. I do my best to improve in maths but after entering in the examination hall during my exams, i just get confused. please help The proper name for the subject is mathematics or just "math" for …
  2. MAth!PLease Help!

    5. Find the x and y intercepts of each linear equation. Be sure to write your answers as ordered pairs. a.y=3x-6 b.6y=-x+2 Set x = 0 and y = 0 to find the intercepts. will that get me 2 thingys for each.?
  3. Math Analysis

    Tell if the function is symmetric with respect to the x-axis, y-axis, and origin. 3. 8x^2 - 2y^2 = 12 ==> I got that it was symmetric to both the x- and y-axes. Is this right?
  4. Math

    Determine the zeros of the function 3x^2 -8=10x. I know I rewrite it as 3x^2 -10x-8 = 0 But then what do I do-I'm totally confused-Answers are {-2,4} {2,4} {-2/3,4} {2/3,4} Please direct me or show the steps, just don't give me the …
  5. algebra

    Find the inverse of the following function. Find the domain, range, and asymptotes of each function. Graph both functions on the same coordinate plane -x/3 f(x)=4+e ( if this makes sense, not sure how else to show it. the -x/3 is after …
  6. Trig

    Let f and g be two invertible functions such that f^-1(x)=5/x+4 and g(x)=4(x-2). Find f(g(5)). Show your steps please so I can see how to do it. Thank you! :)
  7. math

    Find the equation of the tangent line to the graph of f(x) = 2x − 6/x + 1 at the point at which x = 0. (Let x be the independent variable and y be the dependent variable.) I got this question wrong. I thought the answer would …
  8. PHYSICS 1

    The vector signs are above each letter (I just don't know how to show it that way) A= 145 units @ 190 deg. B= 75 units @ 288 deg. C= 210 units @ 85 deg. D= 105 units @ 355 deg. How do I use the component Method with these given magnitude …
  9. Biochem

    You prepare a 1L solution of 0.5 M imidazole. (pKa= 7.05). Calculate the pH of the solution after you add 0.1 moles of HCl. I need to create an ICE table. I also know I need to use the Henderson- Hasselbalch equation but I'm confused …
  10. Math, Algebra

    I asked these questions yesterday and thanked whomever helping me before clicking the links. When the links were just google searches, however, they didn't help me seeing as I already did that. The google search calculator doesn't …

More Similar Questions