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If a ball is thrown vertically upward with a velocity of 160 ft/s, then its height after t seconds is s = 160t - 16t^2

What is the velocity of the ball when it is 96 ft above the ground on its way up?

  • calculus -

    Solve the equation
    16t^2 -160t +96 = 0
    There will be two roots. Take the lowest t value as the solution. That will be the answer when the ball is going up.

    Note that the equation can be simplifed to
    t^2 -10t + 16 = 0
    which factors easily.

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