1). 3x + 7 = 9
2). -3(x + 5) + 3 = 12
Can you also please show the work so that I may have a better understanding.
1). 3x + 7 = 9
subtract 7 from both sides
3 x = 2
divide both sides by 3
x = 2/3
2). -3(x + 5) + 3 = 12
subtract 3 from both sides
-3(x+5) = 9
divide both sides by -3
x+5 = -3
subtract 5 from both sides
x = -8
so easy
i don't know what to do
Sure! Let's solve each equation step-by-step.
1) 3x + 7 = 9
To solve for x, we want to get rid of the 7 on the left side of the equation. We can do this by subtracting 7 from both sides of the equation:
3x + 7 - 7 = 9 - 7
Simplifying, we have:
3x = 2
Now, we need to isolate x. We can do this by dividing both sides of the equation by 3:
(3x)/3 = 2/3
Simplifying once again, we get:
x = 2/3
So, the solution to the equation 3x + 7 = 9 is x = 2/3.
Now, let's move on to the second equation:
2) -3(x + 5) + 3 = 12
First, we need to simplify the expression inside the parentheses by multiplying -3 with each term:
-3x - 15 + 3 = 12
Now, we can simplify further:
-3x - 12 = 12
We need to isolate the x term, so let's get rid of the constant term (-12) on the left side by adding 12 to both sides:
-3x - 12 + 12 = 12 + 12
This simplifies to:
-3x = 24
To isolate x, we divide both sides of the equation by -3:
(-3x) / -3 = 24 / -3
Simplifying once more, we get:
x = -8
Therefore, the solution to the equation -3(x + 5) + 3 = 12 is x = -8.
I hope this explanation helps you understand the process of solving these equations! Let me know if you have any other questions.