Trig  Identies/equation, please help!
posted by James .
2Sin(Θ+47°)=1 ΘЄ[0°, 360°)
What I did:
Sin(Θ+47°)=1/2
Sin 1/2 = Θ+47°
30°+360 = Θ+47°
343° = Θ
Ok, so how do i find the other solutions? In this problem its 103°. I think we were suppose to do something with the graphing calculator and something about calculating the zero. I know how to do that, but i don't know how to make it equal 0 so i could put it in Y1? Any other way, what did i do wrong? Is there a prgm that is avilable for the Ti83+ that can do these problems?
btw:
Θ = theta
Thanks in advance.

whtis the value of 343... figure that out .. and thn u can say that other solutions with be 2 pie ( n)
n wht ever value u figure out in radioans.. 
That looks like an equation, not an identity. If it were an identity, it would be true for all theta.
I am confused about what your symbol on the right side,
1 ΘЄ[0°, 360°)
is supposed to mean
Are you solving 2 Sin(Θ+47°)= 1 ?
If so, Sin(Θ+47°)=0.5
Θ+47° = 30, 150 or 390 degrees
Θ = 103 or 333 degrees if you are limited to theta between 0 and 360 degrees 
the ΘЄ[0°, 360°) was suppose to mean its 0° < or = Θ < 360°

I get this now!!, Thanks!!!, i guess i should study now.