Trig  tan 15° using composite argument?
posted by Anonymous .
tan 15°
tan (45°30°)
(tan 45°  tan 30°)/1+ tan 45°tan30°
(1√3/3)/(1+1√3/3)
then i donnt what to do/ chancel out. Can someone finish it if i didn't get it wrong.
thanks in advance

Trig  tan 15° using composite argument? 
bobpursley
I would rationalize the denominator
(11/3 sqrt3)^2/(11/3)=3(11/3 sqrt3)^2/2
Respond to this Question
Similar Questions

Integration
Intergrate ¡ì sec^3(x) dx could anybody please check this answer. are the steps correct? 
calculus
can anyone tell me if tan1x= 1 over tan x? 
Calculus
Evaluate the limit as h > 0 of: [tan (pi/6 + h)  tan(pi/6)]/h I thought the answer was √3/3, or tan(pi/6, but apparently that is wrong, any tips here? 
trig
h t t p : / / i m g 4 0 . i m a g e s h a c k . u s / c o n t e n t . p h p ? 
Trig.
sec^2xcotxcotx=tanx (1/cos)^2 times (1/tan)(1/tan)=tan (1/cos^2) times (2/tan)=tan (2/cos^2tan)times tan=tan(tan) sq. root of (2/cos^2)= sq. root of (tan^2) sq. root of (2i)/cos=tan I'm not sure if I did this right. If I didn't, … 
trig
please help me. use trig. identities to find the exact value. tan 25° + tan 5° / 1 tan 25° tan 5° 
maths
Derivative of √ tan x is, Answer: A. sin 2 x/ √ tan x B. cos 2 x/ 2 √ tan x C. sec 2 x D. None of these 
Trigonometry
Find the exact value of tan(ab) sin a = 4/5, 3pi/2<a<pi; tan b = sqrt2, pi/2<b<pi identity used is: tan(ab)=(tan atan b)/1+tan a tan b simplify answer using radicals. (a is alpha, b is beta) 
MathTrigonometry
Show that if A, B, and C are the angles of an acute triangle, then tan A + tan B + tan C = tan A tan B tan C. I tried drawing perpendiculars and stuff but it doesn't seem to work? 
TrigWeird Geometry Problem
Determine all triangles ABC for which tan(AB)+tan(BC)+tan(CA)=0. There's a hint: "Can you relate AB to BC and CA?