Trig  tan 15° using composite argument?
posted by Anonymous .
tan 15°
tan (45°30°)
(tan 45°  tan 30°)/1+ tan 45°tan30°
(1√3/3)/(1+1√3/3)
then i donnt what to do/ chancel out. Can someone finish it if i didn't get it wrong.
thanks in advance

I would rationalize the denominator
(11/3 sqrt3)^2/(11/3)=3(11/3 sqrt3)^2/2
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