how do you rearrange 1.1513/sqrt(f)=ln(Re*sqrt(f)/2.51)

to get it in terms of f and also rearrange it in terms of Re?

if you identify an initial estimate of the solution for f when Re=5000 how do you plot on a scatter graph (using something like 0 to 0.1 in increments of 0.01) to identify an initial guess of f?

To rearrange the equation 1.1513/sqrt(f) = ln(Re*sqrt(f)/2.51) in terms of f, you can follow these steps:

Step 1: Multiply both sides of the equation by sqrt(f) to eliminate the square root on the left side:
1.1513 = ln(Re*sqrt(f)/2.51) * sqrt(f)

Step 2: Remove the natural logarithm using exponential function:
e^(1.1513) = Re*sqrt(f)/2.51 * sqrt(f)

Step 3: Simplify the right-hand side:
e^(1.1513) = Re * f / 2.51

Step 4: Multiply both sides by 2.51 to isolate Re*f:
2.51 * e^(1.1513) = Re * f

Therefore, the equation 1.1513/sqrt(f) = ln(Re*sqrt(f)/2.51) can be rearranged as f = (2.51 * e^(1.1513)) / Re to solve for f, and as Re = (2.51 * e^(1.1513)) / f to solve for Re.

To plot the initial estimate of the solution for f when Re = 5000, you can create a scatter graph with f values ranging from 0 to 0.1 in increments of 0.01:

Step 1: Choose a range of f values from 0 to 0.1 in increments of 0.01. For example, f = 0, 0.01, 0.02, ..., 0.1.

Step 2: Use the equation Re = (2.51 * e^(1.1513)) / f to calculate the corresponding Re values for each f value.

Step 3: Plot the f values along the x-axis and the corresponding Re values along the y-axis on a scatter graph.

Step 4: Plot a point on the graph for the initial estimate of the solution when Re = 5000 by locating the f value that corresponds to Re = 5000 and marking it on the graph.

By following these steps, you can plot the scatter graph and identify an initial guess of f based on the corresponding Re value.