write your answer in standard form with integer coefficients.
2x+3y=30; (2,-5)
i don't understand how to do this, im not quiet sure i know what its asking.
the line must go through the point and must be parallel. im soory.
In that case the slope of the line is
-2/3,
since the given line can be written in y = mx + b form as
y = (-2/3)x = 10
The line you want has the equation
[y-(-5)] = (-2/3)(x-2)
which can be rewritten
y + 5 = -(2/3)x +4/3
y = (-2/3)x - 11/3
Write your answer in standard form with integer coefficients. 2x+3y=30; (2,-5)
That is a parallel line to the given line and contains the given point.
To write the equation in standard form with integer coefficients, we need to rearrange the equation in the form of Ax + By = C, where A, B, and C are integers.
Given the equation 2x + 3y = 30, we can move the x-term to the left side by subtracting 2x from both sides:
3y = -2x + 30
Next, we can move the y-term to the left side by subtracting 3y from both sides:
-2x - 3y = 30
Now, the equation is in standard form with integer coefficients. It can also be written as:
-2x - 3y + 30 = 0
As for the point (2, -5), it doesn't relate directly to converting the equation to standard form. However, you can substitute the values of x and y in the equation to check if the point satisfies it. If the equation is true when you substitute the x and y values, then the point lies on the line represented by the equation.
I don't know what you are asking either. The point (2,-5) is not on the line whose equation is 2x+3y=30
You may have left out an earlier part of the question.
Are are asking you for the equation of a line that goes through (2,-5) AND is parallel or perpendicular to the line
2x+3y=30 ?