paul orders a pizza. chef carl randomly chooses two different toppings to put on the pizza from the following:~ pepperoni, onion, sausage, mushrooms and anchovies.
if paul does not eat pizza with mushrooms, determine the probablity that paul will not eat the pizza that chef carl made.
is it 1/5????
There are 5!/(2!*3!) = 120/12 = 10 ways of picking two toppings from five. There are 4 two-topping combinations that do have mushrooms.
Therefore the chances of there being mushrooms on the pizza are 2 in 5.
Given that S is the central atom, draw a Lewis structure of OSF4 in which the formal charges of all atoms are
help ?
Given that S is the central atom, draw a Lewis structure of OSF4 in which the formal charges of all atoms are
help ?
Write a Lewis structure of OSF4 in which the formal charges of all atoms are zero
single bonds on all S to F's, double bond on S to O. Then count valence electrons and add appropriately.
To determine the probability that Paul will not eat the pizza Chef Carl made, we need to calculate the number of favorable outcomes (pizzas without mushrooms) divided by the number of possible outcomes.
Given that Chef Carl chooses two different toppings from pepperoni, onion, sausage, mushrooms, and anchovies, let's calculate the number of possible outcomes.
First, we need to determine how many combinations of two toppings can be made from the five options. This can be calculated using the formula for combinations:
nCr = n! / (r! * (n-r)!)
where n is the total number of options and r is the number of choices.
In this case, n = 5 (the five toppings) and r = 2 (Chef Carl chooses two toppings).
So, the number of possible outcomes is:
5C2 = 5! / (2! * (5-2)!) = (5 * 4) / (2 * 1) = 10
Now, let's determine the number of favorable outcomes (pizzas without mushrooms). Since Paul does not eat pizza with mushrooms, we need to calculate the number of combinations (topping choices) that don't include mushrooms.
Out of the five toppings, if we exclude mushrooms, there are still four remaining options. And Chef Carl needs to choose two toppings out of these four options.
Therefore, the number of favorable outcomes (pizzas without mushrooms) is:
4C2 = 4! / (2! * (4-2)!) = (4 * 3) / (2 * 1) = 6
To find the probability, we divide the number of favorable outcomes by the number of possible outcomes:
Probability = Number of favorable outcomes / Number of possible outcomes
= 6 / 10
= 3/5
So, the probability that Paul will not eat the pizza that Chef Carl made is 3/5, not 1/5 as you suggested.