If you weighed yourself on regular bathroom scale outside, then again inside the Empire State Building and inside your weigh about 350 grams less, why would this be?
If a moon rock was melted, and it tasted like cheese, why would this be?
Why are you trying to explain something that isn't?
Are you maybe on a falling elevator in the building?
I agree it seems odd, yet it really was posed as a real question (maybe by a mad scientist) but, I still owed it some thought and came up with nothing in my books. So again, A man compared his weight from outside the Empire State Building to inside which shows a loss of 350 grams- anything that could explain why this man could of experenced this weight loss inside?
actally, not falling as in a normal elevator, it has to be accelerating downward. So it could be an elevator going upward, but then stopping (in that brief instant when it is deaccelerating), or it could be in an elevator just starting downward.
Yes,I looked at the elavator theory but this question was places the man inside the building on the groundfloor of the looby-no elavator involved.
There may be the mass of the building above him pulling him up, but no way it is going to make that much difference.
Yea, I thought about the mass of the building pulling him up but I didn't know if 350grams would be to much to account for this. I know that people have recorded weight difference in relation to location, that is they lost weight in proportion to the decrease in gravity-I am really struggling to get this.
Yes, gravity is not the same everywhere on earth, but it takes something on the scale of a mountain range to make a serious difference.
Your weight will depend upon how high up you go in the Empire State building, but if you just go inside and stay on the main floor, where should be no change. The relative decrease in g (and weight) at the top floor is only about [1 - (3999.8 miles/4000miles)^2]= 0.01%
The most likely reason for weighing about 350 grams less inside the Empire State Building compared to weighing yourself on a regular bathroom scale outside is due to the difference in the acceleration due to gravity between the two locations.
To understand this, we need to know that weight is the force exerted on an object due to gravity. The magnitude of this force is determined by the mass of the object and the acceleration due to gravity at that location.
The acceleration due to gravity varies slightly depending on the location on Earth. At the Earth's surface, the average value is about 9.8 meters per second squared (m/s²). However, this value changes at different altitudes due to factors such as the shape of the Earth and the distribution of mass.
The Empire State Building is quite tall, so as you ascend to a higher altitude inside the building, you move slightly farther away from the center of the Earth, where gravity is slightly weaker compared to the surface. This decrease in gravitational acceleration leads to a reduction in the force exerted on your body, resulting in a lower weight reading on the scale.
To calculate the exact difference in weight, we could use the formula:
Weight = mass x acceleration due to gravity
Let's assume your mass is constant. You weighed yourself on the regular bathroom scale outside, and the scale showed a weight of W1. Inside the Empire State Building, the scale showed a weight of W2, which is approximately 350 grams less than W1.
We can set up an equation:
W1 = mass x acceleration due to gravity at the Earth's surface
W2 = mass x acceleration due to gravity at the Empire State Building
Since the mass is constant, we can rearrange the equation as:
W2 = W1 - 350 grams
By performing this calculation, taking into account the approximate difference in gravitational acceleration at the surface and high altitude, we would find the weight difference inside the Empire State Building compared to outside.