A midwestern music competition awarded 38 ribbons. The number of blue ribbons awarded was 3 less than the number of white ribbons. The number of red ribbons was 2 more than the number of white ribbons. How many of each kind of ribbon was awarded?

Question

A midwestern music competition awarded 38 ribbons. The number of blue ribbons awarded was 3 less than the number of white ribbons. The number of red ribbons was 2 more than the number of white ribbons. How many of each kind of ribbon was awarded?

Answer 1

w+(w-3)+(w+2)= 38

Solve this equation to get the number of white ribbons then plug in that number to solve for the rest of the ribbons

Answer 2

first you add one to both sides

3w-1=38
+1 +1

then you divide both sides by 3
3w=39
/3 /3

then when you get your answer...
w=13

go back and plug in 13 in every w.Remember to follow the order of operations

13+(13-3)+(13+2)=38
13+(10)+(15)=38
38+38

:D

Answer 3

Let's denote the number of white ribbons as 'W'.

According to the given information, the number of blue ribbons awarded was 3 less than the number of white ribbons, which means the number of blue ribbons is (W - 3).

The number of red ribbons was 2 more than the number of white ribbons, which means the number of red ribbons is (W + 2).

We know that the total number of ribbons awarded is 38.

So, we can write the equation:
W + (W - 3) + (W + 2) = 38

Now, let's solve this equation to find the value of W.

Combining like terms:
3W - 1 = 38

Adding 1 to both sides:
3W = 39

Dividing both sides by 3:
W = 13

Now, we know that the number of white ribbons is 13.

Substituting the value of W back into our expressions for blue and red ribbons:

Number of blue ribbons = (W - 3) = (13 - 3) = 10

Number of red ribbons = (W + 2) = (13 + 2) = 15

Therefore, there were 13 white ribbons, 10 blue ribbons, and 15 red ribbons awarded.

Answer 4

To solve this problem, we need to set up a system of equations based on the given information.

Let's assign variables to the unknowns:
Let's say the number of white ribbons awarded is x
The number of blue ribbons awarded would then be x - 3 (since it's 3 less than the number of white ribbons)
And the number of red ribbons awarded would be x + 2 (since it's 2 more than the number of white ribbons)

According to the problem, the total number of ribbons awarded is 38. Therefore, we can write the equation:

x + (x - 3) + (x + 2) = 38

Now, let's solve for x:

3x - 1 = 38
3x = 38 + 1
3x = 39
x = 39 / 3
x = 13

So, the number of white ribbons awarded is 13.
The number of blue ribbons awarded would be x - 3 = 13 - 3 = 10.
The number of red ribbons awarded would be x + 2 = 13 + 2 = 15.

Therefore, there were 13 white ribbons, 10 blue ribbons, and 15 red ribbons awarded in the competition.