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A midwestern music competition awarded 38 ribbons. The number of blue ribbons awarded was 3 less than the number of white ribbons. The number of red ribbons was 2 more than the number of white ribbons. How many of each kind of ribbon was awarded?

  • math -

    w+(w-3)+(w+2)= 38
    Solve this equation to get the number of white ribbons then plug in that number to solve for the rest of the ribbons

  • math -

    first you add one to both sides
    3w-1=38
    +1 +1

    then you divide both sides by 3
    3w=39
    /3 /3

    then when you get your answer...
    w=13

    go back and plug in 13 in every w.Remember to follow the order of operations

    13+(13-3)+(13+2)=38
    13+(10)+(15)=38
    38+38

    :D

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