# calculus

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find the limit for the given function

lim (sin)^2(3 t))/t^2
t->0

• calculus -

Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.

OR use the fact that sin x approaches x as x-> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9

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