calculus
posted by kat .
find the limit for the given function
lim (sin)^2(3 t))/t^2
t>0

calculus 
drwls
Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.
OR use the fact that sin x approaches x as x> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9
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