# Engineering/Algebra

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A cardboard tube has a failure stress of 4,960,000 N/m^2 and an axial stress of 75 N/cm^2, find the factor of safety of the tube.

• Engineering/Algebra -

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75 N/cm^2 * (10^4 cm^2/m^2) = 7.5*10^5 N/m^2
4.96*10^6 / 7.5*10^5 = 49.6 / 7.5 = 6.61

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