intermediate algebra
posted by jennifer .
Find the equation of the line that pass through the given point and is perpendicular to the given line. Write in slope intercept form.
(0,0), y + 3x = 12
would I subtract 3x from both sides?
if so would the slope be 3x?
m = 1/3 , (0,0)
yy1, m(xx1)
y0=1/3(x0)
y0=1/3 x+0
y0+0=1/3x
this is where i get lost.
any help please

Rewrite it as y = (1/3)x 12
That tells you that the slope of the original line is 1/3. The slope of the perpendicular line must be 3, because the product of the two slopes must be 1.
Since the new line passes through the origin, its equation is just y = 3x