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In rolling a pair of dice, suppose you win $5 if the sum is 10 but lose $2 if the roll is "doubles." If the price to play is $1, would it be a fair game? Justify your answer.

  • math -

    The probability of throwing a "10" with a pair of dice is 3/36 = 1/12. The probability of throwing "doubles" is 6/36 = 1/6.

    Probable gain for $1 bet =
    (1/12)*5 - (1/6)*2 = $ 1/12

    The game favors the bettor

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