I've been given the Volume of Concentrated NaOh solution (mL) and also the Concentration of Concentrated NaOh solution (M).
I also have the volume of stock solution after dilution (mL).
The question is asking the approximate concentration of stock solution (M)
any help?
Your question lacks clarity. Some numbers and how these solutions were prepared would help.
If you know the molarity of the stock solution..you know how many moles you want.
For instance, if you want 0.06M of NaOH of stock solution, 1.400ml of it.
So the moles of NaOH in the stock solution will be .06*1.4 = .084 moles.
You have 12M conc solution.
so you need .084 moles of this.
molarity=moles/volume or
volume=moles/molarity=.084/12=.007 liters, or 7ml.
So 7ml of conc NaOH should be added to sufficient water to make up 1.4liters of solution.
i kinda understand waht you're saying. to be a bit more clear this is from a lab,
and here are the volumes we retrieved:
Volume of Concentrated NaOH soultion (mL) = 9.00 mL
Concentration of Concentrated NaOH soultuon (M) = 6.00 M
Volume of Stock Solution after Dilution (mL) = 490.00 mL + 9.00 mL (from the first part)
and then the question says the give the Approximate concentration of Stock solution (M).
It says to use the formula: amount of solute (moles) / volume of solution (L)
I'm confused with how to get amount of solute with the 6.00 M and 9.00mL volume.
How many mols NaOH did you start with. M x L = 6.00 M x 0.009 L = ??
When it was diluted you still had ?? mols NaOH. What is the final volume? That is 490.00 + 9.00 mL = 499.00 mL or 0.499 L.
Now M of the diluted solution is mols/L = ??mols/0.499 L. Voila!
OMG, i totally understand that. DrBob222, THANK YOU VEYR MUCH!
Yes, I can help you with that. To find the approximate concentration of the stock solution (M), you can use the dilution formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the concentrated NaOH solution (M)
V1 = initial volume of the concentrated NaOH solution (mL)
C2 = final concentration of the stock solution (M)
V2 = final volume of the stock solution after dilution (mL)
In this case, you have been given the initial volume (V1) and concentration (C1) of the concentrated NaOH solution, as well as the final volume (V2) of the stock solution after dilution. You need to find the final concentration (C2) of the stock solution.
To solve for C2, rearrange the formula:
C2 = (C1 * V1) / V2
Substitute the given values into the equation, and calculate the final concentration (C2) of the stock solution. Make sure that the volume units are consistent (in this case, mL).
Please note that the calculated value will only be an approximation, as the dilution process might not be 100% efficient.