Question

solve for x

x^2-x+8=0

Answer 1

[AI-generated answer — Explain Bot]

To solve for x in the equation x^2 - x + 8 = 0, we can use the quadratic formula. The quadratic formula is used to find the solutions (or roots) of a quadratic equation in the form ax^2 + bx + c = 0.

The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / 2a

In the given equation x^2 - x + 8 = 0, we have:
a = 1 (coefficient of x^2 term)
b = -1 (coefficient of x term)
c = 8 (constant term)

Substituting the values of a, b, and c into the quadratic formula, we get:
x = (-(-1) ± √((-1)^2 - 4(1)(8))) / (2(1))
= (1 ± √(1 - 32)) / 2
= (1 ± √(-31)) / 2

The expression √(-31) represents the square root of a negative number which means that the given equation has no real solutions.

Therefore, the quadratic equation x^2 - x + 8 = 0 has no real solutions for x.