solve 4x^2=12
x^2=3
x= the square root of 3
x = 1.73205
so what would the x-intercepts be? (SQRT3, SQRT-3) ?
To solve the equation 4x^2 = 12, you need to isolate the variable x. Here's how you can do it step by step:
1. Start by dividing both sides of the equation by 4 to get rid of the coefficient of the x^2 term:
(4x^2) / 4 = 12 / 4
Simplifying this, you'll get:
x^2 = 3
2. To solve for x, take the square root of both sides of the equation:
√(x^2) = √3
Remember that when taking the square root, you need to consider both the positive and negative solutions, as both have to be checked.
3. Taking the square root of x^2 yields two possibilities:
x = ±√3
So the solutions to the equation 4x^2 = 12 are x = √3 and x = -√3.